ASP.NET 简单的 JSON 处理实现 Ajax 功能

var ajax = {

    setDebugMode: function(){
        this.debugMode = true;
    },

    get: function (requestUrl, data, loaderImageId, onSuccess, onComplete) {

        if (loaderImageId) {
            $("#" + loaderImageId).css('display', 'inline');
        }

        var completeFunction = function () {
            if (onComplete) {
                onComplete();
            }
            if (loaderImageId) {
                $("#" + loaderImageId).css('display', 'none');
            }
        };

        $.ajax({
            type: "GET",
            url: requestUrl,
            data: data,
            context: this,
            success: function (response) {
                onSuccess(response);
                completeFunction();
            },
            error: function (response) {
                alert("Ajax Request Failed");
                this.showError(response);
                completeFunction();
            }
        });
    },

    post: function (requestUrl, data, loaderImageId, onSuccess, onComplete) {

        if (loaderImageId) {
            $("#" + loaderImageId).css('display', 'inline');
        }

        var completeFunction = function () {
            if (onComplete) {
                onComplete();
            }
            if (loaderImageId) {
                $("#" + loaderImageId).css('display', 'none');
            }
        };

        $.ajax({
            type: "POST",
            url: requestUrl,
            context: this,
            data: data,
            success: function (response) {
                onSuccess(response);
                completeFunction();
            },
            error: function (response) {
                alert("Ajax Request Failed");
                this.showError(response);
                completeFunction();
            }
        });
    },

    showError: function(requestObject){
        if (this.debugMode){
            alert(requestObject.responseText);
        }
    }
};