Java中Request请求转发详解

2020-10-08 0 764

直接来,RequestDemo5代码,get请求和post请求都请求转发了,转发到RequestDemo6请求

 RequestDemo5代码

package com.lingaolu.request;
 
import javax.servlet.RequestDispatcher;
import javax.servlet.ServletException;
import javax.servlet.annotation.WebServlet;
import javax.servlet.http.*;
import java.io.IOException;
 
/**
 * @author 林高禄
 * @create 2020-07-07-12:06
 */
@WebServlet(\"/requestDemo5\")
public class RequestDemo5 extends HttpServlet {
 
 @Override
 protected void doPost(HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException {
 System.out.println(\"requestDemo5进来了......post\");
 RequestDispatcher requestDispatcher = request.getRequestDispatcher(\"/requestDemo6\");
 requestDispatcher.forward(request,response);
 }
 
 @Override
 protected void doGet(HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException {
 System.out.println(\"requestDemo5进来了......get\");
 RequestDispatcher requestDispatcher = request.getRequestDispatcher(\"/requestDemo6\");
 requestDispatcher.forward(request,response);
 
 }
}

RequestDemo6代码

package com.lingaolu.request;
 
import javax.servlet.ServletException;
import javax.servlet.annotation.WebServlet;
import javax.servlet.http.*;
import java.io.IOException;
 
/**
 * @author 林高禄
 * @create 2020-07-07-12:06
 */
@WebServlet(\"/requestDemo6\")
public class RequestDemo6 extends HttpServlet {
 
 @Override
 protected void doPost(HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException {
 System.out.println(\"requestDemo6进来了......post\");
 }
 
 @Override
 protected void doGet(HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException {
 System.out.println(\"requestDemo6进来了......get\");
 }
}

浏览器访问/requestDemo5接口

Java中Request请求转发详解

控制台输出

Java中Request请求转发详解

从以上结果可以看出

请求过后我们的浏览器地址还是http://localhost:8080/myRequest/requestDemo5

从浏览器的F12调试页面可以看出,转发只是一次请求,只有/requestDemo5请求,说明,可共享数据Request共享数据

我们用Postman进行post请求一下

Java中Request请求转发详解

后台输出:

Java中Request请求转发详解

可见,get请求的转发会转发到get请求,post请求的转发,会转发到post请求

我们改一下RequestDemo5的代码,转发到百度

package com.lingaolu.request;
 
import javax.servlet.RequestDispatcher;
import javax.servlet.ServletException;
import javax.servlet.annotation.WebServlet;
import javax.servlet.http.*;
import java.io.IOException;
 
/**
 * @author 林高禄
 * @create 2020-07-07-12:06
 */
@WebServlet(\"/requestDemo5\")
public class RequestDemo5 extends HttpServlet {
 
 @Override
 protected void doPost(HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException {
 System.out.println(\"requestDemo5进来了......post\");
 RequestDispatcher requestDispatcher = request.getRequestDispatcher(\"/requestDemo6\");
 requestDispatcher.forward(request,response);
 }
 
 @Override
 protected void doGet(HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException {
 System.out.println(\"requestDemo5进来了......get\");
 RequestDispatcher requestDispatcher = request.getRequestDispatcher(\"https://www.baidu.com/\");
 requestDispatcher.forward(request,response);
 
 }
}

浏览器请求

Java中Request请求转发详解

 后台输出:

Java中Request请求转发详解

从后台输出看出,requestDemo5请求进来了,从浏览器看出,转发失败了,而且从实际转发的路径上看,因为虚拟路径,所以请求转发只能转发到当前服务器内部的资源

请求转发的特点总结:(与之对应的——重定向的详情与特点

  • 浏览器地址栏路径不发生变化
  • 转发只是一次请求,可共享数据Request共享数据
  • 哪种请求方式只能转发到那种请求方式
  • 请求转发只能转发到当前服务器内部的资源

到此这篇关于JavaRequest请求转发详解的文章就介绍到这了,更多相关Java Request请求转发内容请搜索自学编程网以前的文章或继续浏览下面的相关文章希望大家以后多多支持自学编程网!

遇见资源网 JAVA Java中Request请求转发详解 http://www.ox520.com/19545.html

常见问题

相关文章

发表评论
暂无评论
官方客服团队

为您解决烦忧 - 24小时在线 专业服务