井字棋,英文名叫Tic-Tac-Toe,是一种在3*3格子上进行的连珠游戏,和五子棋类似,由于棋盘一般不画边框,格线排成井字故得名。游戏需要的工具仅为纸和笔,然后由分别代表O和X的两个游戏者轮流在格子里留下标记(一般来说先手者为X),任意三个标记形成一条直线,则为获胜。
游戏的难点在于,如何判断连接成了一条线;横、竖、斜三个方向;
游戏的代码:
#!/usr/bin/env python3 # -*- coding:utf-8 -*- u\'\'\' Created on 2019年4月13日 @author: wuluo \'\'\' __author__ = \'wuluo\' __version__ = \'1.0.0\' __company__ = u\'重庆交大\' __updated__ = \'2019-04-13\' # 创建井字棋的程序 def initBoard(): global board # 调用全局的board board = [None] * 3 print(\"井字棋:\") for i in range(len(board)): board[i] = [\"+ \"] * 3 # 打印井字棋的程序 def printBoard(): global board for i in range(len(board)): for j in range(len(board[i])): print(board[i][j], end=\" \") print(\"\") # 开始下棋的程序 def startGame(): global board player = 0 while isGameContinue(): if player <= 8: if player % 2 == 0: # 甲方下棋 print(\"==>黑方下棋\") if not playChess(\"x\"): continue else: # 乙方下棋 print(\"==>白方下棋\") if not playChess(\"○\"): continue player += 1 else: print(\"平局\") break def playChess(chess): # 获取位置 x = int(input(\"==> X=\")) - 1 y = int(input(\"==> Y=\")) - 1 if board[x][y] == \"+ \": board[x][y] = chess printBoard() return True # 落子成功 else: print(\"==> 已有棋子 请重新落子\\a\") printBoard() return False # 落子失败 def isGameContinue(): for i in range(len(board)): for j in range(len(board[i])): if board[i][j] != \"+ \": # 横向 if j == 0: if board[i][j] == board[i][j + 1] == board[i][j + 2]: whoWin(i, j) return False # 竖向 if i == 0: if board[i][j] == board[i + 1][j] == board[i + 2][j]: whoWin(i, j) return False # 正斜 if i == 0 and j == 0: if board[i][j] == board[i + 1][j + 1] == board[i + 2][j + 2]: whoWin(i, j) return False # 反斜 if i == 2 and j == 0: if board[i][j] == board[i - 1][j + 1] == board[i - 2][j + 2]: whoWin(i, j) return False return True def whoWin(i, j): if board[i][j] == \"x\": print(\"黑方胜!\") else: print(\"白方胜!\") for i in range(3): print(\"win\") class main(): board = [] initBoard() printBoard() startGame() if __name__ == \"__main__\": main()
游戏结果:
还有一种结果是平局:
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