python入门之井字棋小游戏

引言：

刚学python好几天了，从java到python，基础学起来确实比较容易，语法掌握，基本概念上都比较容易入脑。

唯一比较郁闷的是老想着用java的语法去学python代码，这点还需要后面慢慢掌握吧，相信学多种语言的你们也有这种经历吧。

start：开始上代码了，希望有更好的逻辑思维来写，自己也是用最笨拙的思路去写的，如果有可以优化的代码请各位大神指教

#!/user/bin/python
# -*- coding: utf-8 -*-
import os
import sys
#棋盘模块
def model(dictionary,serial=False):
 if serial:
  print(\'-(初版)井字棋游戏,输入棋号进行对战,\')
  print(\'对应棋号为第一行:a1-a2-a3\',end=\',\')
  print(\'对应棋号为第二行:b1-b2-b3\',end=\',\')
  print(\'对应棋号为第三行:c1-c2-c3\')
 print(dictionary[\'a1\'] + \' | \'+ dictionary[\'a2\'] +\' | \'+ dictionary[\'a3\'] +\' | \')
 print(\'- +- +- +-\')
 print(dictionary[\'b1\'] + \' | \' + dictionary[\'b2\'] + \' | \' + dictionary[\'b3\'] + \' | \')
 print(\'- +- +- +-\')
 print(dictionary[\'c1\'] + \' | \' + dictionary[\'c2\'] + \' | \' + dictionary[\'c3\'] + \' | \')
#主模块
def main():
 dictionary={\'a1\':\' \',\'a2\':\' \',\'a3\':\' \',\'b1\':\' \',\'b2\':\' \',\'b3\':\' \',\'c1\':\' \',\'c2\':\' \',\'c3\':\' \'}
 model(dictionary, True)
 u1 = \'x\' #用户1
 u2 = \'o\' #用户2
 stepNumber =1 #记录步数
 break_fang = 0 #获胜者记录
 while(stepNumber<=9):
 fv = True # 判断条件2
 while fv:
  num = input(\'请用户u1开始下棋:\')
  compare=1 #判断条件1
  for x in dictionary:
  if x.find(num)!=-1:compare=0
  if compare ==0:
  fv=False
 dictionary[num] = u1
 model(dictionary)
 # 0:继续 1,用户1胜,2,用户2胜
 break_fang = forResult(dictionary)
 if break_fang > 0: break
 fv =True #清楚状态
 stepNumber+=1
 while fv:
  num1=input(\'请用户u2开始下棋:\')
  compare = 1 # 判断条件1
  for x in dictionary:
  if x.find(num1)!=-1:compare=0
  if compare == 0:
  fv=False
 dictionary[num1] = u2
 model(dictionary)
 break_fang = forResult(dictionary)
 if break_fang > 0: break
 stepNumber+=1
 gameover(break_fang)
#退出下棋
def gameover(break_fang):
 c = input(\'是否重新开始? yes:no:\')
 if c.find(\'yes\')!=-1:
 main()
 else:
 print(\'-游戏结束-\')
 return
#判断获胜情况
#dictionary:棋盘信息
def forResult(dictionary):
 dicts= dict(dictionary)
 if dicts[\'a1\'] == dicts[\'a2\'] and dicts[\'a2\'] == dicts[\'a3\'] and len(dicts[\'a3\'].strip())>0:
 print(\'游戏结束,\' + \'用户1-获胜\' if dicts[\'a1\'] == \'x\' else \'用户2-获胜\')
 return 1 if dicts[\'a1\']==\'x\' else 2
 elif dicts[\'a1\'] == dicts[\'b2\'] and dicts[\'b2\'] == dicts[\'c3\'] and len(dicts[\'c3\'].strip())>0:
 print(\'游戏结束,\' + \'用户1-获胜\' if dicts[\'a1\'] == \'x\' else \'用户2-获胜\')
 return 1 if dicts[\'a1\'] == \'x\' else 2
 elif dicts[\'a1\'] == dicts[\'b1\'] and dicts[\'b1\'] == dicts[\'c1\'] and len(dicts[\'c1\'].strip())>0:
  print(\'游戏结束,\' + \'用户1-获胜\' if dicts[\'a1\'] == \'x\' else \'用户2-获胜\')
  return 1 if dicts[\'a1\'] == \'x\' else 2
 elif dicts[\'a2\'] == dicts[\'b2\'] and dicts[\'b2\'] == dicts[\'c2\'] and len(dicts[\'c2\'].strip())>0:
 print(\'游戏结束,\' + \'用户1-获胜\' if dicts[\'a2\'] == \'x\' else \'用户2-获胜\')
 return 1 if dicts[\'a2\'] == \'x\' else 2
 elif dicts[\'a3\'] == dicts[\'b3\'] and dicts[\'b3\'] == dicts[\'c3\'] and len(dicts[\'c3\'].strip())>0:
  print(\'游戏结束,\' + \'用户1-获胜\' if dicts[\'a3\'] == \'x\' else \'用户2-获胜\')
  return 1 if dicts[\'a3\'] == \'x\' else 2
 elif dicts[\'a3\'] == dicts[\'b2\'] and dicts[\'b3\'] == dicts[\'c1\'] and len(dicts[\'c1\'].strip())>0:
  print(\'游戏结束,\' + \'用户1-获胜\' if dicts[\'a3\'] == \'x\' else \'用户2-获胜\')
  return 1 if dicts[\'a3\'] == \'x\' else 2
 elif dicts[\'b1\'] == dicts[\'b2\'] and dicts[\'b2\'] == dicts[\'b3\'] and len(dicts[\'b3\'].strip())>0:
  print(\'游戏结束,\' + \'用户1-获胜\' if dicts[\'b1\'] == \'x\' else \'用户2-获胜\')
  return 1 if dicts[\'b1\'] == \'x\' else 2
 elif dicts[\'c1\'] == dicts[\'c2\'] and dicts[\'c2\'] == dicts[\'c3\'] and len(dicts[\'c3\'].strip())>0:
  print(\'游戏结束,\' + \'用户1-获胜\' if dicts[\'c1\'] == \'x\' else \'用户2-获胜\')
  return 1 if dicts[\'c1\'] == \'x\' else 2
 else:
 return 0
if __name__ ==\'__main__\':
 main()

补一点更改思路:forResult()的另一种实现,compares()函数:少了6行代码量。

def compares(dictionary={\'\':\'\'},string=\'\'):
 if len(dictionary)>0 | len(string.strip())==0:print(\'传值为空!\')
 else:
 axle =(\'a1\',\'a3\',\'b2\',\'c1\',\'c3\') # 四个角和中间的数特殊判断 条件1
 axle_fang=False #特殊棋号需要多加一种可能性
 for x in axle:
  if string==x:axle_fang=True
 if axle_fang: #条件1
  if dictionary[\'a1\']==dictionary[\'b2\'] and dictionary[\'b2\']==dictionary[\'c3\'] and dictionary[\'c3\'].strip()!=\'\'\\
   or dictionary[\'a3\']==dictionary[\'b2\'] and dictionary[\'b2\']==dictionary[\'c1\']and dictionary[\'c1\'].strip()!=\'\':
   print(\'游戏结束,\' + \'用户1-获胜\' if dictionary[string] == \'x\' else \'用户2-获胜\')
   return 1 if dictionary[string] == \'x\' else 2
 # 拆分棋号 splitStr0,splitStr1,普通棋号只需判断俩种a俩种可能,上下-左右间的位置
 splitStr0,splitStr1 = string[0],string[1]
 print(splitStr0+\":\"+splitStr1)
 if dictionary[splitStr0+\'1\']==dictionary[splitStr0+\'2\'] and dictionary[splitStr0+\'2\']==dictionary[splitStr0+\'3\']\\
  or dictionary[\'a\'+splitStr1]==dictionary[\'b\'+splitStr1] and dictionary[\'b\'+splitStr1]==dictionary[\'c\'+splitStr1]:
  print(\'游戏结束,\' + \'用户1-获胜\' if dictionary[string] == \'x\' else \'用户2-获胜\')
  return 1 if dictionary[string] == \'x\' else 2
 else:return 0

end：写完这些也有九十行代码量了，总感觉太多了。

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