使用Django的JsonResponse返回数据的实现

urls.py

from django.conf.urls import url
from . import views

urlpatterns = [
  url(r\'^show/\', views.show_view, name=\'show\')
]

在views.py中创建show_view函数

from django.http import HttpResponse
from django.shortcuts import render
from .models import *
from django.core.paginator import Paginator, PageNotAnInteger, EmptyPage
from django.http import JsonResponse
def show_view(request):
  # 获取当前页码数
  num = request.GET.get(\'num\', 1)
  n = int(num)
  # 1.查询stu_student表中的所有数据
  stus = Student.objects.all() # 获取所有的
  # django 分页
  pager = Paginator(stus, 2)
  # 获取当前页面的数据
  try:
    stuss = Student.objects.all().values()
    students = list(stuss)
    return JsonResponse({\'code\': 200, \'data\': students})
    perpage_data = pager.page(n)
    # 返回第一页的数据
  except PageNotAnInteger:
    perpage_data = pager.page(1)
    # 返回最后一页的数据
  except EmptyPage:
    perpage_data = pager.page(pager.num_pages)
  return render(request, \'show.html\', {\'show\': stus, \'pager\': pager, \'perpage_data\': perpage_data})