python通过re正则表达式切割中英文的操作

我就废话不多说了,大家还是直接看代码吧~

import re 
s = \'alibaba阿里巴巴\' # 待分割字符串
en_letter = \'[\\u0041-\\u005a|\\u0061-\\u007a]+\' # 大小写英文字母
zh_char = \'[\\u4e00-\\u9fa5]+\' # 中文字符
 
print(re.findall(zh_char,s) + re.findall(en_letter,s))
 
# 输出: [\'阿里巴巴\', \'alibaba\']
范围 说明
\\u4e00-\\u9fa5 汉字的unicode范围
\\u0030-\\u0039 数字的unicode范围
\\u0041-\\u005a 大写字母unicode范围
\\u0061-\\u007a 小写字母unicode范围

补充:python–中英文混合字符串的切分(中文按字断开,英文按单词分开,数字按空格等特殊符号断开)

待切分句子:

s = \”12、China\’s Legend Holdings will split its several business arms to go public on stock markets, the group\’s president Zhu Linan said on Tuesday.该集团总裁朱利安周二表示,haha中国联想控股将分拆其多个业务部门在股市上市,。\”

切分结果:

[\’12\’, \’china\’, \’s\’, \’legend\’, \’holdings\’, \’will\’, \’split\’, \’its\’, \’several\’, \’business\’, \’arms\’, \’to\’, \’go\’, \’public\’, \’on\’, \’stock\’, \’markets\’, \’the\’, \’group\’, \’s\’, \’president\’, \’zhu\’, \’linan\’, \’said\’, \’on\’, \’tuesday\’, \’该\’, \’集\’, \’团\’, \’总\’, \’裁\’, \’朱\’, \’利\’, \’安\’, \’周\’, \’二\’, \’表\’, \’示\’, \’haha\’, \’中\’, \’国\’, \’联\’, \’想\’, \’控\’, \’股\’, \’将\’, \’分\’, \’拆\’, \’其\’, \’多\’, \’个\’, \’业\’, \’务\’, \’部\’, \’门\’, \’在\’, \’股\’, \’市\’, \’上\’, \’市\’]

代码:

import re
def get_word_list(s1):
  # 把句子按字分开,中文按字分,英文按单词,数字按空格
  regEx = re.compile(\'[\\\\W]*\')  # 我们可以使用正则表达式来切分句子,切分的规则是除单词,数字外的任意字符串
  res = re.compile(r\"([\\u4e00-\\u9fa5])\")  # [\\u4e00-\\u9fa5]中文范围
  p1 = regEx.split(s1.lower())
  str1_list = []
  for str in p1:
    if res.split(str) == None:
      str1_list.append(str)
    else:
      ret = res.split(str)
      for ch in ret:
        str1_list.append(ch)
  list_word1 = [w for w in str1_list if len(w.strip()) > 0] # 去掉为空的字符
  return list_word1
if __name__ == \'__main__\':
  s = \"12、China\'s Legend Holdings will split its several business arms to go public on stock markets, the group\'s president Zhu Linan said on Tuesday.该集团总裁朱利安周二表示,haha中国联想控股将分拆其多个业务部门在股市上市。\"
  list_word1=get_word_list(s)
  print(list_word1)

以上为个人经验,希望能给大家一个参考,也希望大家多多支持。如有错误或未考虑完全的地方,望不吝赐教。

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