目录
- 1.字符串反转
- 2.每个单词的第一个字母大写
- 3.字符串查找唯一元素
- 4.重复打印字符串和列表n次
- 5.列表生成
- 6.变量交换
- 7.字符串拆分为子字符串列表
- 8.多个字符串组合为一个字符串
- 9.检测字符串是否为回文
- 10.统计列表中元素的次数
- 11.判断两个字符串是否为Anagrams
- 12.使用try-except-else-block模块
- 13.使用枚举函数得到key/value对
- 14.检查对象的内存使用情况
- 15.合并字典
- 16.计算执行一段代码所花费的时间
- 17.列表展开
- 18.列表采样
- 19.数字化
- 20.检查列表元素的唯一性
Python的可读性和简单性是其广受欢迎的两大原因,本文介绍20个常用的Python技巧来提高代码的可读性,并能帮助你节省大量时间,下面的技巧将在你的日常编码练习中非常实用。
1.字符串反转
使用Python切片反转字符串:
# Reversing a string using slicing my_string = \"ABCDE\" reversed_string = my_string[::-1] print(reversed_string) # Output # EDCBA
2.每个单词的第一个字母大写
使用title函数方法:
my_string = \"my name is chaitanya baweja\" # using the title() function of string class new_string = my_string.title() print(new_string) # Output # My Name Is Chaitanya Baweja
3. 字符串查找唯一元素
使用集合的概念查找字符串的唯一元素:
my_string = \"aavvccccddddeee\" # converting the string to a set temp_set = set(my_string) # stitching set into a string using join new_string = \'\'.join(temp_set) print(new_string) # output # cdvae
4.重复打印字符串和列表n次
你可以使用乘法符号(*)打印字符串或列表多次:
n = 3 # number of repetitions my_string = \"abcd\" my_list = [1,2,3] print(my_string*n) # abcdabcdabcd print(my_list*n) # [1,2,3,1,2,3,1,2,3]
5.列表生成
# Multiplying each element in a list by 2 original_list = [1,2,3,4] new_list = [2*x for x in original_list] print(new_list) # [2,4,6,8]
6.变量交换
a = 1 b = 2 a, b = b, a print(a) # 2 print(b) # 1
7.字符串拆分为子字符串列表
使用.split()函数:
string_1 = \"My name is Chaitanya Baweja\" string_2 = \"sample/ string 2\" # default separator \' \' print(string_1.split()) # [\'My\', \'name\', \'is\', \'Chaitanya\', \'Baweja\'] # defining separator as \'/\' print(string_2.split(\'/\')) # [\'sample\', \' string 2\']
8.多个字符串组合为一个字符串
list_of_strings = [\'My\', \'name\', \'is\', \'Chaitanya\', \'Baweja\'] # Using join with the comma separator print(\',\'.join(list_of_strings)) # Output # My,name,is,Chaitanya,Baweja
9.检测字符串是否为回文
my_string = \"abcba\" if my_string == my_string[::-1]: print(\"palindrome\") else: print(\"not palindrome\") # Output # palindrome
10. 统计列表中元素的次数
# finding frequency of each element in a list from collections import Counter my_list = [\'a\',\'a\',\'b\',\'b\',\'b\',\'c\',\'d\',\'d\',\'d\',\'d\',\'d\'] count = Counter(my_list) # defining a counter object print(count) # Of all elements # Counter({\'d\': 5, \'b\': 3, \'a\': 2, \'c\': 1}) print(count[\'b\']) # of individual element # 3 print(count.most_common(1)) # most frequent element # [(\'d\', 5)]
11.判断两个字符串是否为Anagrams
Anagrams的含义为两个单词中,每个英文单词(不含大小写)出现的次数相同,使用Counter类判断两个字符串是否为Anagrams。
from collections import Counter str_1, str_2, str_3 = \"acbde\", \"abced\", \"abcda\" cnt_1, cnt_2, cnt_3 = Counter(str_1), Counter(str_2), Counter(str_3) if cnt_1 == cnt_2: print(\'1 and 2 anagram\') if cnt_1 == cnt_3: print(\'1 and 3 anagram\') # output # 1 and 2 anagram
12. 使用try-except-else-block模块
except获取异常处理:
a, b = 1,0 try: print(a/b) # exception raised when b is 0 except ZeroDivisionError: print(\"division by zero\") else: print(\"no exceptions raised\") finally: print(\"Run this always\") # output # division by zero # Run this always
13. 使用枚举函数得到key/value对
my_list = [\'a\', \'b\', \'c\', \'d\', \'e\'] for index, value in enumerate(my_list): print(\'{0}: {1}\'.format(index, value)) # 0: a # 1: b # 2: c # 3: d # 4: e
14.检查对象的内存使用情况
import sys num = 21 print(sys.getsizeof(num)) # In Python 2, 24 # In Python 3, 28
15.合并字典
dict_1 = {\'apple\': 9, \'banana\': 6} dict_2 = {\'banana\': 4, \'orange\': 8} combined_dict = {**dict_1, **dict_2} print(combined_dict) # Output # {\'apple\': 9, \'banana\': 4, \'orange\': 8}
16.计算执行一段代码所花费的时间
使用time类计算运行一段代码所花费的时间:
import time start_time = time.time() # Code to check follows for i in range(10**5): a, b = 1,2 c = a+ b # Code to check ends end_time = time.time() time_taken_in_micro = (end_time- start_time)*(10**6) print(time_taken_in_micro) # output # 18770.217895507812
17. 列表展开
from iteration_utilities import deepflatten # if you only have one depth nested_list, use this def flatten(l): return [item for sublist in l for item in sublist] l = [[1,2,3],[3]] print(flatten(l)) # [1, 2, 3, 3] # if you don\'t know how deep the list is nested l = [[1,2,3],[4,[5],[6,7]],[8,[9,[10]]]] print(list(deepflatten(l, depth=3))) # [1, 2, 3, 4, 5, 6, 7, 8, 9, 10]
18. 列表采样
import random my_list = [\'a\', \'b\', \'c\', \'d\', \'e\'] num_samples = 2 samples = random.sample(my_list,num_samples) print(samples) # [ \'a\', \'e\'] this will have any 2 random values
19.数字化
将整数转化成数字列表
num = 123456 # using map list_of_digits = list(map(int, str(num))) print(list_of_digits) # [1, 2, 3, 4, 5, 6] # using list comprehension list_of_digits = [int(x) for x in str(num)] print(list_of_digits) # [1, 2, 3, 4, 5, 6]
20.检查列表元素的唯一性
检查列表中每个元素是否为唯一的:
def unique(l): if len(l)==len(set(l)): print(\"All elements are unique\") else: print(\"List has duplicates\") unique([1,2,3,4]) # All elements are unique unique([1,1,2,3]) # List has duplicates
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